n^2=2809

Solution for n^2=2809 equation:

n^2=2809

We move all terms to the left:

n^2-(2809)=0

a = 1; b = 0; c = -2809;
Δ = b2-4ac
Δ = 02-4·1·(-2809)
Δ = 11236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11236}=106$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-106}{2*1}=\frac{-106}{2}
=-53
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+106}{2*1}=\frac{106}{2}
=53
$